Searched refs:nContCount (Results 1 – 2 of 2) sorted by relevance
493 long nContCount = aFollow.getLength(); in repeatMultiple() local495 for (long nPos=0; nPos<nContCount; nPos++) in repeatMultiple()
1519 sal_Int32 nContCount = 0; in lcl_FilterInclude() local1528 ++nContCount; in lcl_FilterInclude()1533 nContCount = 0; in lcl_FilterInclude()1570 rSubtotal[j] = nContCount + 1 + nSubTotalCount; in lcl_FilterInclude()
Completed in 13 milliseconds