Searched refs:pNodeX (Results 1 – 2 of 2) sorted by relevance
300 double* pNodeX, in interpolate() argument313 sum *= x - pNodeX[ n ]; in interpolate()314 sum /= pNodeX[ i ] - pNodeX[ n ]; in interpolate()
117 double interpolate( double x, double* pNodeX, double* pNodeY, int nNodes );
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