Searched refs:lngStartLine (Results 1 – 1 of 1) sorted by relevance
489 Dim lngStartLine As Long variable494 lngStartLine = 1508 Do While vbcm.Find(strFind, lngStartLine, _512 If InStr(1, vbcm.Lines(lngStartLine, 1), "VBFindLines") <> 0 Then519 strProc = vbcm.ProcOfLine(lngStartLine, lngType)524 strProc = vbcm.ProcOfLine(lngStartLine, lngType)529 vbLf & vbcm.Lines(lngStartLine, 1) & vbLf531 strProc = vbcm.Lines(lngStartLine, 1)540 " - " & lngStartLine & " ]" & vbLf547 lngStartLine = lngEndLine + 1[all …]
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